tt::has_inequivalence< T, U > Struct Template Reference

Check if type T has operator!= defined. More...

#include <HasInequivalence.hpp>

Detailed Description

template<typename T, typename U = void>
struct tt::has_inequivalence< T, U >

Check if type T has operator!= defined.

Details

Inherits from std::true_type if the type T has operator!= defined, otherwise inherits from std::false_type

Usage

For any type T,

using result = tt::has_inequivalence<T>;

Returns: std::bool_constant

Semantics: If the type T has operator!= defined, then

typename result::type = std::true_type;

otherwise

typename result::type = std::false_type;

Example

static_assert(not tt::has_inequivalence<A>::value,
              "Failed testing type trait has_inequivalence");
static_assert(tt::has_inequivalence<TestHelpers::C>::value,
              "Failed testing type trait has_inequivalence");
static_assert(tt::has_inequivalence_t<TestHelpers::C>::value,
              "Failed testing type trait has_inequivalence");
static_assert(tt::has_inequivalence_v<TestHelpers::C>,
              "Failed testing type trait has_inequivalence");

See also

has_equivalence

Template Parameters

T	the type we want to know if it has operator!=

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The documentation for this struct was generated from the following file:

• src/Utilities/TypeTraits/HasInequivalence.hpp