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       1           1 : // Distributed under the MIT License.
       2             : // See LICENSE.txt for details.
       3             : 
       4             : /// \file
       5             : /// Defines the class FlatOffsetSphericalWedge.
       6             : 
       7             : #pragma once
       8             : 
       9             : #include <array>
      10             : #include <cstddef>
      11             : #include <limits>
      12             : #include <optional>
      13             : 
      14             : #include "DataStructures/Tensor/TypeAliases.hpp"
      15             : 
      16             : /// \cond
      17             : namespace PUP {
      18             : class er;
      19             : }  // namespace PUP
      20             : /// \endcond
      21             : 
      22             : namespace domain::CoordinateMaps {
      23             : 
      24             : /*!
      25             :  * \ingroup CoordinateMapsGroup
      26             :  *
      27             :  * \brief Map from a cube to a volume that connects four planes and
      28             :  * portions of two spherical surfaces.
      29             :  *
      30             :  * \image html FlatOffsetSphericalWedge.svg "Slices of FlatOffsetSphericalWedge"
      31             :  *
      32             :  * \details A cube is mapped to the volume shown in the figure.
      33             :  *
      34             :  * A $y=0$ slice through the volume is shown in the left
      35             :  * panel of the figure, and a $x=$const slice through the volume is shown
      36             :  * in the right panel of the figure.
      37             :  *
      38             :  * The lower-$z$ face of the volume is a portion of a spherical surface
      39             :  * of radius $R_1$ centered about point $C$ in the figure, which is along
      40             :  * the $x$-axis a distance $D$ from the origin (point $O$ in the figure).
      41             :  * The upper-$z$ face of the volume is a portion of a spherical surface
      42             :  * of radius $R_2$ centered about the origin.
      43             :  *
      44             :  * The lower-$x$ face of the volume is a portion of the plane at constant
      45             :  * $x=0$, and the upper-$x$ face of the volume is a portion of the plane
      46             :  * at constant $x=D$. See the $x$ extents of the left panel of the
      47             :  * figure.
      48             :  *
      49             :  * Every constant-$x$ cross section of the volume looks like the right
      50             :  * panel of the figure: it is a two-dimensional wedge with 45 degree
      51             :  * opening angle.  Both the inner and outer radii of this wedge vary
      52             :  * with $x$: The inner radius of the wedge is $R_1$ at $x=D$ and
      53             :  * $\sqrt{R_1^2-D^2}$ at $x=0$, and the outer radius of the wedge is
      54             :  * $R_2$ at $x=0$ and $\sqrt{R_2^2-D^2}$ at $x=D$.
      55             :  *
      56             :  * ### Relation to FlatOffsetWedge
      57             :  *
      58             :  * The lower-$z$ face of this FlatOffsetSphericalWedge is the same as
      59             :  * the upper-$z$ face of the similar map FlatOffsetWedge; Blocks using
      60             :  * these two maps are meant to abut at this surface.  The parameter
      61             :  * $D$ means the same thing for the two maps, and the parameter $R$ in
      62             :  * FlatOffsetWedge is the same as what we call $R_1$ here.
      63             :  * For abutting blocks, the corresponding parameters of the two maps should
      64             :  * be equal, and both maps should have the same origin.
      65             :  *
      66             :  * The formulas below will be similar to those of the FlatOffsetWedge map,
      67             :  * but slightly more complicated.
      68             :  *
      69             :  * ### Restrictions
      70             :  *
      71             :  * We require $D<R_1$ or else the lower-$x$ face of the mapped
      72             :  * volume lies outside of the sphere of radius $R_1$.
      73             :  * We also require that $R_2^2 > R_1^2+D^2$ or else the outer sphere
      74             :  * and inner sphere will intersect at the upper-$x$ face and the map
      75             :  * will be singular.
      76             :  *
      77             :  * ## Equations for the map
      78             :  * Given our cube coordinates $\xi,\eta,\zeta$, each taking on values from
      79             :  * $-1$ to $+1$, we can derive the formulas for the map.
      80             :  *
      81             :  * Define
      82             :  * \begin{align}
      83             :  *    q &\equiv \frac{D}{2R_1},\\
      84             :  *    v &\equiv \frac{R_1}{R_2}.
      85             :  * \end{align}
      86             :  *
      87             :  * Notice that $q<1/2$, because of the restriction $D<R_1$.  Also we
      88             :  * must have $v < \left(1+4q^2\right)^{-1/2}$ because of the
      89             :  * restriction $R_2^2 > R_1^2+D^2$.
      90             :  *
      91             :  * Note that $x$ is a function of $\xi$ only, for all points in the volume:
      92             :  * \begin{align}
      93             :  *  x(\xi,\eta,\zeta) &= q R (\xi+1).
      94             :  * \end{align}
      95             :  *
      96             :  * ### Surface map for bottom and top surfaces
      97             :  * The $y$ and $z$ coordinates of the bottom surface,
      98             :  * $\zeta=-1$, of the volume are given by
      99             :  * \begin{align}
     100             :  *   \begin{bmatrix}
     101             :  *      y(\xi,\eta,+1)\\
     102             :  *      z(\xi,\eta,+1)
     103             :  *   \end{bmatrix} =
     104             :  *     \frac{R_1}{\sqrt{1+\eta^2}}
     105             :  *               \sqrt{1-q^2(\xi-1)^2}
     106             :  *   \begin{bmatrix}
     107             :  *      \eta \\
     108             :  *      1
     109             :  *   \end{bmatrix}.
     110             :  * \end{align}
     111             :  * This is the same formula as for the upper face of the similar
     112             :  * FlatOffsetWedge map.
     113             :  *
     114             :  * The $y$ and $z$ coordinates for the mapped $\zeta=+1$ surface are
     115             :  * \begin{align}
     116             :  *   \begin{bmatrix}
     117             :  *      y(\xi,\eta,+1)\\
     118             :  *      z(\xi,\eta,+1)
     119             :  *   \end{bmatrix} =
     120             :  *     \frac{R_2}{\sqrt{1+\eta^2}}
     121             :  *              \sqrt{1-v^2q^2(\xi+1)^2}
     122             :  *   \begin{bmatrix}
     123             :  *      \eta \\
     124             :  *      1
     125             :  *   \end{bmatrix}.
     126             :  * \end{align}
     127             :  * Because of the above restrictions on $v$ and $q$, and because $\xi$ and
     128             :  * $\eta$ range between $-1$ and $+1$, the arguments of the square
     129             :  * roots above are always positive.
     130             :  *
     131             :  * ### Full volume map
     132             :  * Adding the $\zeta$ dependence by linear interpolation gives us
     133             :  * the full volume map for the $y$ and $z$ coordinates:
     134             :  *
     135             :  * \begin{align}
     136             :  *   \begin{bmatrix}
     137             :  *      y(\xi,\eta,\zeta)\\
     138             :  *      z(\xi,\eta,\zeta)
     139             :  *   \end{bmatrix} =
     140             :  *      \left[\frac{1+\zeta}{2}
     141             :  *        \frac{R_2}{\sqrt{1+\eta^2}}
     142             :  *                   \sqrt{1-v^2q^2(\xi+1)^2}
     143             :  *        + \frac{1-\zeta}{2}
     144             :  *          \frac{R_1}{\sqrt{1+\eta^2}}
     145             :  *           \sqrt{1-q^2(\xi-1)^2}\right]
     146             :  *   \begin{bmatrix}
     147             :  *      \eta \\
     148             :  *      1
     149             :  *   \end{bmatrix}.
     150             :  * \end{align}
     151             :  *
     152             :  * ## Inverse
     153             :  *
     154             :  * The map can be inverted analytically:
     155             :  *
     156             :  * \begin{align}
     157             :  *    \xi   &= \frac{x}{qR}-1\\
     158             :  *    \eta  &= \frac{y}{z}\\
     159             :  *    \zeta &= \frac{2z - W - P}{W-P},
     160             :  *              \label{eq:zetaFromxyz}
     161             :  * \end{align}
     162             :  * where
     163             :  * \begin{align}
     164             :  *   P &\equiv R_1\frac{\sqrt{1-(x-D)^2/R_1^2}}{\sqrt{1+y^2/z^2}}\\
     165             :  *     &= R_1\frac{\sqrt{1-q^2(\xi-1)^2}}{\sqrt{1+\eta^2}},
     166             :  *              \label{eq:Pdefinition} \\
     167             :  *   W &\equiv R_2\frac{\sqrt{1-x^2/R_2^2}}{\sqrt{1+y^2/z^2}}\\
     168             :  *     &= R_2\frac{\sqrt{1-v^2q^2(\xi+1)^2}}{\sqrt{1+\eta^2}}.
     169             :  *              \label{eq:Wdefinition}
     170             :  * \end{align}
     171             :  *
     172             :  * It is easy to determine whether a point $(x,y,z)$ lies within the volume:
     173             :  * First compute $\xi$ and $\eta$ and check that they are both in $[-1,1]$.
     174             :  * If so, then the arguments of the square roots in
     175             :  * Eq. ($\ref{eq:Pdefinition}$) and Eq. ($\ref{eq:Wdefinition}$) are
     176             :  * guaranteed positive, and the denominator
     177             :  * of Eq. ($\ref{eq:zetaFromxyz}$) is guaranteed positive
     178             :  * by our condition $v < 1/\sqrt{1+4q^2}$.
     179             :  * Then it is straightforward to
     180             :  * compute $\zeta$ and then check if it is in $[-1,1]$.
     181             :  *
     182             :  * ## Jacobian
     183             :  *
     184             :  * Straightforward differentiation gives
     185             :  *
     186             :  * \begin{align}
     187             :  *    \frac{\partial x}{\partial \xi}   &= qR_1,\\
     188             :  *    \frac{\partial x}{\partial \eta}   &= 0,\\
     189             :  *    \frac{\partial x}{\partial \zeta}   &= 0,\\
     190             :  *   \partial_\zeta \begin{bmatrix}
     191             :  *      y\\
     192             :  *      z
     193             :  *   \end{bmatrix} &= \frac{W-P}{2}
     194             :  *   \begin{bmatrix}
     195             :  *      \eta \\
     196             :  *      1
     197             :  *   \end{bmatrix}, \\
     198             :  *   \partial_\xi \begin{bmatrix}
     199             :  *      y\\
     200             :  *      z
     201             :  *   \end{bmatrix} &=
     202             :  *    \frac{q^2}{2}\left[
     203             :  *    P\frac{(1-\zeta)(1-\xi)}{1-q^2(1-\xi)^2}
     204             :  *    -W\frac{v^2(1+\zeta)(1+\xi)}{1-v^2q^2(1+\xi)^2}
     205             :  *    \right]
     206             :  *   \begin{bmatrix}
     207             :  *      \eta \\
     208             :  *      1
     209             :  *   \end{bmatrix}, \\
     210             :  *   \partial_\eta \begin{bmatrix}
     211             :  *      y\\
     212             :  *      z
     213             :  *   \end{bmatrix} &=
     214             :  *       -\frac{\eta}{2(1+\eta^2)}\left[
     215             :  *        W(1+\zeta)
     216             :  *       +P(1-\zeta)\right]
     217             :  *   \begin{bmatrix}
     218             :  *      \eta \\
     219             :  *      1
     220             :  *   \end{bmatrix}+
     221             :  *   \begin{bmatrix}
     222             :  *      z \\
     223             :  *      0
     224             :  *   \end{bmatrix}.
     225             :  * \end{align}
     226             :  *
     227             :  * Although it is straightforward to construct the inverse jacobian
     228             :  * analytically, for now we compute the inverse jacobian by numerically taking
     229             :  * the matrix inverse of the jacobian.
     230             :  *
     231             :  */
     232           1 : class FlatOffsetSphericalWedge {
     233             :  public:
     234           0 :   static constexpr size_t dim = 3;
     235             :   /*!
     236             :    * \brief Constructs a FlatOffsetSphericalWedge.
     237             :    *
     238             :    * \param lower_face_x_width The width $D$ of the lower face in
     239             :    * the $x$ direction.
     240             :    * \param inner_radius The inner radius $R_1$.
     241             :    * \param outer_radius The outer radius $R_2$.
     242             :    */
     243           1 :   FlatOffsetSphericalWedge(double lower_face_x_width, double inner_radius,
     244             :                            double outer_radius);
     245             : 
     246           0 :   FlatOffsetSphericalWedge() = default;
     247           0 :   ~FlatOffsetSphericalWedge() = default;
     248           0 :   FlatOffsetSphericalWedge(FlatOffsetSphericalWedge&&) = default;
     249           0 :   FlatOffsetSphericalWedge(const FlatOffsetSphericalWedge&) = default;
     250           0 :   FlatOffsetSphericalWedge& operator=(const FlatOffsetSphericalWedge&) =
     251             :       default;
     252           0 :   FlatOffsetSphericalWedge& operator=(FlatOffsetSphericalWedge&&) = default;
     253             : 
     254             :   template <typename T>
     255           0 :   std::array<T, 3> operator()(const std::array<T, 3>& source_coords) const;
     256             : 
     257             :   /// The inverse function is only callable with doubles because the inverse
     258             :   /// might fail if called for a point out of range, and it is unclear
     259             :   /// what should happen if the inverse were to succeed for some points in a
     260             :   /// DataVector but fail for other points.
     261           1 :   std::optional<std::array<double, 3>> inverse(
     262             :       const std::array<double, 3>& target_coords) const;
     263             : 
     264             :   template <typename T>
     265           0 :   tnsr::Ij<T, 3, Frame::NoFrame> jacobian(
     266             :       const std::array<T, 3>& source_coords) const;
     267             : 
     268             :   template <typename T>
     269           0 :   tnsr::Ij<T, 3, Frame::NoFrame> inv_jacobian(
     270             :       const std::array<T, 3>& source_coords) const;
     271             : 
     272             :   // clang-tidy: google runtime references
     273           0 :   void pup(PUP::er& p);  // NOLINT
     274             : 
     275           0 :   static bool is_identity() { return false; }
     276             : 
     277           0 :   static constexpr bool supports_hessian{false};
     278             : 
     279             :  private:
     280           0 :   friend bool operator==(const FlatOffsetSphericalWedge& lhs,
     281             :                          const FlatOffsetSphericalWedge& rhs);
     282           0 :   double lower_face_x_width_{std::numeric_limits<double>::signaling_NaN()};
     283           0 :   double inner_radius_{std::numeric_limits<double>::signaling_NaN()};
     284           0 :   double outer_radius_{std::numeric_limits<double>::signaling_NaN()};
     285             : };
     286             : 
     287           0 : bool operator!=(const FlatOffsetSphericalWedge& lhs,
     288             :                 const FlatOffsetSphericalWedge& rhs);
     289             : }  // namespace domain::CoordinateMaps

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